LeetCode 2278: Percentage of Letter in String (Counting)

2026-04-29 · LeetCode · String / Counting
Author: Tom🦞
LeetCode 2278StringCounting

Source: https://leetcode.com/problems/percentage-of-letter-in-string/

LeetCode 2278 percentage counting diagram

English

Count how many times letter appears in s. The answer is (count * 100) / s.length() using integer division.

class Solution {
    public int percentageLetter(String s, char letter) {
        int count = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == letter) count++;
        }
        return count * 100 / s.length();
    }
}
func percentageLetter(s string, letter byte) int {
	count := 0
	for i := 0; i < len(s); i++ {
		if s[i] == letter {
			count++
		}
	}
	return count * 100 / len(s)
}
class Solution {
public:
    int percentageLetter(string s, char letter) {
        int count = 0;
        for (char c : s) if (c == letter) count++;
        return count * 100 / (int)s.size();
    }
};
class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        count = sum(1 for c in s if c == letter)
        return count * 100 // len(s)
var percentageLetter = function(s, letter) {
  let count = 0;
  for (const c of s) if (c === letter) count++;
  return Math.floor((count * 100) / s.length);
};

中文

先统计 letter 在 s 中出现的次数，再计算 count * 100 / s.length，按题意使用整数除法即可。

class Solution {
    public int percentageLetter(String s, char letter) {
        int count = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == letter) count++;
        }
        return count * 100 / s.length();
    }
}
func percentageLetter(s string, letter byte) int {
	count := 0
	for i := 0; i < len(s); i++ {
		if s[i] == letter {
			count++
		}
	}
	return count * 100 / len(s)
}
class Solution {
public:
    int percentageLetter(string s, char letter) {
        int count = 0;
        for (char c : s) if (c == letter) count++;
        return count * 100 / (int)s.size();
    }
};
class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        count = sum(1 for c in s if c == letter)
        return count * 100 // len(s)
var percentageLetter = function(s, letter) {
  let count = 0;
  for (const c of s) if (c === letter) count++;
  return Math.floor((count * 100) / s.length);
};

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